Namio590 Namio590
  • 06-02-2021
  • Mathematics
contestada

F(x)=bx^2+32 For the function f defined above, b is a constant and f(2)=40. What is the value of f(-2)?

Respuesta :

ajeigbeibraheem
ajeigbeibraheem ajeigbeibraheem
  • 07-02-2021

Answer:

f(-2) = 0

Step-by-step explanation:

Given that:

f(x) = bx^2 + 32

f(2) = b(2)^2 + 32

f(2) = 4b + 32

f(2) = 4b = -32

f(2) = b = -32/4

f(2) = b = -8

Thus;

f(-2) = -8(-2)^2 + 32

f(-2) = -8(4) + 32

f(-2) = -32 + 32

f(-2) = 0

Answer Link
junior10152004 junior10152004
  • 09-02-2021

Answer:C

Step-by-step explanation:

yessir

Answer Link

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