I am just going to assume that you are looking the sine, cosine, and tangent of both A and B.
SOHCAHTOA (used for reference).
[tex]Sin A = \frac{8}{10} = \frac{4}{5} \\Cos A = \frac{6}{10} = \frac{3}{5} \\Tan A = \frac{8}{6} = \frac{4}{3} \\Sin B = \frac{6}{10} = \frac{3}{5} \\Cos B = \frac{8}{10} = \frac{4}{5} \\Tan B = \frac{6}{8} = \frac{3}{4} \\[/tex]
