Respuesta :

[tex]12x^2+11x-15 = 0[/tex]

[tex] (4x - 3)(3x + 5) = 0 [/tex]

[tex] (4x - 3) = 0 \ or \ (3x + 5) = 0 [/tex]

[tex]x = \dfrac{3}{4} \ or \ x = -\dfrac{5}{3}[/tex]