Kira1315 Kira1315

09-03-2018
Advanced Placement (AP)

contestada

find the derivative
[tex]y = ln \sqrt{3x} [/tex]

find the derivative texy ln sqrt3x tex class=

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sqdancefan sqdancefan

14-03-2018

y = ln(√(3x)) = (1/2)ln(3x) = (1/2)(ln(3) +ln(x))

dy/dx = (1/2)(0 +1/x) = 1/(2x)

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