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evgeniylevi
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12) for h=√(10²-6²)=8
then 
[tex] \frac{x-6}{8} = \frac{8}{6}; \ =\ \textgreater \ \ x= \frac{50}{3} [/tex]

14) 6:11 as x:10. It means that
[tex] \frac{6}{11} = \frac{x}{10}; \ =\ \textgreater \ \ x=6*10/11= \frac{60}{11} [/tex]

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