Respuesta :

budwilkins
Same method as the last problem:
d: y-2
x: x-0 = x
y: y--2 = y+2
[tex] {y - 2}^{2} = {x}^{2} + {(y + 2)}^{2} \\ {y}^{2} - 4y + 4 = {x}^{2} + {y}^{2} + 4y + 4 \\ - 8y = {x}^{2} \\ y = \frac{ - 1}{8} {x}^{2} [/tex]
C) is the correct answer

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