Respuesta :

Billymkhoi
(2x-2y)(2y+8)
= (2x)*(2y)+(2x)*8-(2y)(2y)-(2y)*8
= 4xy+ 16x- 4y^2- 16y

The correct answer is D. 4xy+ 16x- 4y^2- 16y~
calculista

Answer:

The answer is the option D

[tex]4xy+16x-4y^{2}-16y[/tex]

Step-by-step explanation:

we have

[tex](2x-2y)(2y+8)[/tex]

Multiply applying the distributive property

[tex](2x-2y)(2y+8)=2x*2y+2x*8-2y*2y-2y*8[/tex]

[tex]=4xy+16x-4y^{2}-16y[/tex]

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