Respuesta :

scalar multiplication for a matrix is very straightforward

[tex]\bf -8 \begin{bmatrix} 7&-4&0\\ -3&0&5\\ 6&2&1 \end{bmatrix}\implies \begin{bmatrix} -8\cdot 7&-8\cdot -4&-8\cdot 0\\ -8\cdot -3&-8\cdot 0&-8\cdot 5\\ -8\cdot 6&-8\cdot 2&-8\cdot 1 \end{bmatrix} \\\\\\ \begin{bmatrix} -56&32&0\\ 24&0&-40\\ -48&-16&-8 \end{bmatrix}[/tex]
jacobc72
the correct answer would be A you welcome