g(x) = (25 - x)/5 First lets call g(x) by its other name - y
y = (25 - x)/5 Now switch the x and y
x = (25 - y)/5 Solve for y which is now the inverse - call this [tex] g^{-1}(x) [/tex]
5x = 25 - y
y = 25 - 5x this is the inverse so [tex] g^{-1}(x) [/tex] = 25 - 5x
