allisonlequire1 allisonlequire1
  • 11-12-2017
  • Chemistry
contestada

What is the true, molecular formula of a compound with the empirical formula C13H19O2 and molar mass of 414.64g?

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W0lf93
W0lf93 W0lf93
  • 24-12-2017

C13H19O2 = (12 * 13) + (1 *19) + (16 *2) = 156 + 19 + 32 = 207. 
The formula is n = molar mass of molecular formular / molar mass of empirical formular. MM of molecular formula = 414.7 and of empirical formula =207  
So n = 414.7 / 207 = 2. 
So the true molecular formula is 2(C13H19O9) = C26H38O18.
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