elias4958 elias4958
  • 10-12-2017
  • Mathematics
contestada

Find the magnitude and direction (in degrees) of the vector: v= 〈-√2/2,-√2/2〉

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Аноним Аноним
  • 10-12-2017
Magnitude is  sqrt ( -sqrt2/2 ^2 + -sqrt2/2 ^2)
  = sqrt (0.5 + 0.5)
   = 1
 The vector is in the third quadrant and its tangent = 1  so the angle is 180 + 45
 = 225 degrees


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