[tex]\bf y=-27(x+4)^3+1\implies 0=-27(x+4)^3+1
\\\\\\
-1=-27(x+4)^3\implies \cfrac{-1}{-27}=(x+4)^3\implies \cfrac{1}{27}=(x+4)^3
\\\\\\
\sqrt[3]{\cfrac{1}{27}}=x+4\implies \cfrac{\sqrt[3]{1}}{\sqrt[3]{27}}=x+4\implies \cfrac{1}{3}=x+4\implies \cfrac{1}{3}-4=x
\\\\\\
-\cfrac{11}{3}=x[/tex]
