An airplane initially travels at 10.0 m/s when passing the acceleration line. The airplane then accelerates at 8.00 m/s^2 until reaching its take off velocity of 40.0 m/s. What is the displacement of the plane during acceleration? A) 93.8 B) 3.75 C) 100 D)1590 please explain if able.
The displacement of the plane during acceleration is 93.8 meters. The equation relating displacement, acceleration, and velocity is: Vf^2 = Vi^2 +2*a*d, where Vf is final velocity, Vi is initial velocity, a is acceleration, and d is displacement. Plugging the given values into this equation: 40^2 = (10)^2 + 2*8*d => 1600 = 100+16d => solve for d: d = (1600-100)/16 = 93.8 meters.
