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09-10-2017
Chemistry

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How much work (in J) is involved in a chemical reaction if the volume decreases from 5.00 to 1.48 L against a constant pressure of 0.819 atm?

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Аноним Аноним

19-10-2017

Given:
ΔV = 5 - 1.48 L = 3.52 L = 0.00352 m³, th chane in volume
p = 0.818 atm = 0.819*101325 Pa = 82985.2 Pa

By definition, the work done is
[tex]W = \int pdV = (82985.2 \, \frac{N}{m^{2}} )*(0.00352 \, m^{3}) = 292.1 \, J[/tex]

Answer: 292.1 J

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