[tex]find\ "x"\\\\y=-\frac{2}{3}x+4\ \ \ \ |subtract\ 4\ from\ both\ sides\\\\y-4=-\frac{2}{3}x\ \ \ \ |multiply\ both\ sides\ by\ 3\\\\3y-12=-2x\to-2x=3y-12\ \ \ |divide\ both\ sides\ by\ (-2)\\\\x=\frac{3y}{-2}-\frac{12}{-2}\\\\x=-\frac{3}{2}y+6\\\\Your\ answer:\boxed{y=-\frac{3}{2}x+6}[/tex]
