Respuesta :

naǫ
[tex]a^2+2ab+b^2=(a+b)^2 \\ \Downarrow \\ x^2+4x+4=x^2 + 2 \times 2 \times x +2^2=(x+2)^2 \\ \\ x^2+4x+4=0 \\ (x+2)^2=0 \\ x+2=0 \\ x=-2[/tex]

The answer is B.
solve your equation step-by-step.

x2+4x+4=0

Factor left side of equation.

(x+2)(x+2)=0

Set factors equal to 0.

x+2=0

or

x+2=0


x=−2

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