pamdhuber8315 pamdhuber8315

10-09-2017
Mathematics

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What are the points of discontinuity y=(x-5)/x^2-6x+5?

Respuesta :

Panoyin Panoyin

10-09-2017

[tex]y = \frac{x - 5}{x^{2} - 6x + 5}[/tex]
[tex]y = \frac{x - 5}{(x - 1)(x - 5)}[/tex]
[tex]y = \frac{1}{x - 1}[/tex]

x - 1 = 0
+ 1 + 1
x = 1

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