alishamariyamgeorgeb alishamariyamgeorgeb
  • 10-02-2024
  • Mathematics
contestada

If (a-5)^2 (b-6)^2=0, then find the value of (a+b-3)?

Respuesta :

minnionqueen38
minnionqueen38 minnionqueen38
  • 10-02-2024

Answer:8

Step-by-step explanation:

Given that

(

�

−

5

)

2

(

�

−

6

)

2

=

0

(a−5)

2

(b−6)

2

=0, this implies that either

(

�

−

5

)

2

=

0

(a−5)

2

=0 or

(

�

−

6

)

2

=

0

(b−6)

2

=0, or both are zero.

When

(

�

−

5

)

2

=

0

(a−5)

2

=0,

�

=

5

a=5, and when

(

�

−

6

)

2

=

0

(b−6)

2

=0,

�

=

6

b=6.

So, the sum

�

+

�

−

3

a+b−3 would be:

5

+

6

−

3

=

8

5+6−3=8

Therefore, the value of

�

+

�

−

3

a+b−3 is

8

8.

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