iDentify the equation of the circle that has its center at (-27, 120) and passes through the origin A. (x−27)2+(y+120)2=123 B. (x+27)2+(y−120)2=123 C. (x−27)2+(y+120)2=15129 D. (x+27)2+(y−120)2=15129
The equation of a circle is given in the form [tex](x-a)^2+(y-b)^2=r^2[/tex], where
(a, b) is the centre of the circle r = radius
We have the centre of the circle (-27, 120) We can work out the radius by modelling the radius as the hypotenuse of a triangle as shown in the diagram below
