asdfasdgg6778 asdfasdgg6778
  • 08-08-2017
  • Mathematics
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The region bounded by y=5/x, y=0, x=1, and x=3 is rotated about the x-axis. find the volume of the resulting solid.

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Abu99
Abu99 Abu99
  • 08-08-2017
Volume of Revolution  = [tex] \pi \int\limits^b_a {y^{2}} \, dx [/tex]
Volume of Revolution  = [tex] \pi \int\limits^3_1 { (\frac{5}{x})^{2}} \, dx[/tex]
= [tex]\pi \int\limits^3_1 ({\frac{25}{x^{2}}) \, dx[/tex]
= [tex]25\pi \int\limits^3_1 ({\frac{1}{x^{2}}) \, dx[/tex]
= [tex]25\pi \int\limits^3_1 ({x^{-2}}) \, dx[/tex]
= [tex]25\pi \ ^{3} [-x^{-1}] _{1} [/tex]
[tex]= 25\pi\ ((-1/3) - (-1/1)) \\ = 25\pi\ (2/3) \\ = 50/3 \pi\ units^{3} [/tex]
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