Answer: [tex]y=-\dfrac{1}{3}x[/tex]
Step-by-step explanation:
Equation of a line that passes through two points (a,b) and (c,d) is given by :-
[tex](y-b)=\dfrac{d-b}{c-a}(x-a)[/tex]
The given points : (0, 0) and (-3, 1)
Then, the equation of the line passing through these points :
[tex](y-0)=\dfrac{1-0}{-3-0}(x-0)[/tex]
[tex]\Rightarrow\ y=-\dfrac{1}{3}x[/tex]
Hence, the required equation that passes through (0, 0) and (-3, 1) is [tex]y=-\dfrac{1}{3}x[/tex].