maddyclontz3194 maddyclontz3194

08-07-2017
Mathematics

contestada

What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?k = a0

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texaschic101 texaschic101

08-07-2017

f(x) = 112 - kx
f(-3) = 121

f(-3) = 112 - k(-3)
f(-3) = 112 + 3k
121 = 112 + 3k
121 - 112 = 3k
9 = 3k
9/3 = k
3 = k <===

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NicholasCampbell NicholasCampbell

20-02-2019

Answer:

3

Step-by-step explanation:

the answer is 3

Answer Link

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