Forgetsalot
Forgetsalot Forgetsalot
  • 09-06-2017
  • Mathematics
contestada

[tex] \frac{3}{2n} + \frac{1}{n^2} = \frac{n-2}{2n^2} [/tex]

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apologiabiology
apologiabiology apologiabiology
  • 09-06-2017
make denomenators the same
common denom is 2n²

multiply 3/2n by n/n
mulitply 1/n² by 2/2

we get
[tex] \frac{3n}{2n^2}+\frac{2}{2n^2}=\frac{n-2}{2n^2} [/tex]
combine fractions
[tex] \frac{3n+2}{2n^2}=\frac{n-2}{2n^2} [/tex]
multiply both sides by 2n²
2n+2=n-2
minus n both sides
n+2=-2
minus 2 both sides
n=-4
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