Respuesta :

nafsaeatailii
4c2d + 3dc – 2(dc2 + cd) + 6c2d2
4c2d + 3dc – 2(2+1)cd+6c+2d+2
4c2d + 3dc –2*3cd+6c*2d*2
(4*2+3-2*3+6*2*2)cd
(8+3-6+24)cd
29cd

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Answer:

The answer is 29cd

Step-by-step explanation:

By reducing all the items step by step

4c2d + 3dc – 2(dc2 + cd) + 6c2d2

4*2*c*d + 3*c*d - 2(2*c*d+c*d)+2*2*6*c*d

8cd+3cd-2(2cd+cd)+24cd

11cd-2(3cd)+24cd

11cd-6cd+24cd

29cd

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