Respuesta :

[tex]\bf f(x)=x^2+5\qquad g(x)=5x+4 \\\\\\ (f\circ g)(x)\implies f(\quad g(x)\quad ) \\\\\\ f(\quad g(x)\quad )=[g(x)]^2+5\implies f(\quad g(x)\quad )=[5x+4]^2+5 \\\\\\ f(\quad g(\underline{6})\quad )=[5(\underline{6})+4]^2+5[/tex]

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