carolyns2425 carolyns2425

07-04-2015
Mathematics

contestada

identify the turning point of the function f(x)= x^2-2x+8 by writing its equation in vertex form.

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konrad509 konrad509

08-04-2015

The turning point of a quadratic function is its vertex.

[tex]f(x)=x^2-2x+8\\ f(x)=x^2-2x+1+7\\ f(x)=(x-1)^2+7[/tex]

So the turning point of the above function is [tex](1,7)[/tex]

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