Respuesta :

gmany

[tex]b^m\cdot b^n=b^{n+m}[/tex]


Answer: C. b^m+n


Example

[tex] 2^3\cdot2^4=(\underbrace{2\cdot2\cdot2}_{3})\cdot(\underbrace{2\cdot2\cdot2\cdot2}_{4})=\underbrace{2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2}_{3+4=7}=2^7 [/tex]:



kylemwhite16

Answer:

The answer is b^m+n

Step-by-step explanation:

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