Samslays
Samslays Samslays
  • 07-04-2017
  • Mathematics
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Please help with one Geometry question!! Number 19 only!!! I need to know how to set up the problem

Please help with one Geometry question Number 19 only I need to know how to set up the problem class=

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Аноним Аноним
  • 07-04-2017
We know that the opposite angles are equal
So...

3y - 20 = 2x + 6    and    4x = 4y + 4

That is the system of equations you need to solve
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jdoe0001 jdoe0001
  • 07-04-2017
for the figure to be a parallelogram, opposite angles need to be congruent

that means B = D and A = C

thus [tex]\bf \begin{cases} 3y-20=2x+6\\ -2x+3y=26\\ ----------\\ 4x=4y+4\\ 4x-4y=4\\ x-y=1 \end{cases}\implies \begin{cases} -2x+3y=26\\ x-y=1 \end{cases}[/tex]
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