igobannanas
igobannanas
06-04-2017
Mathematics
contestada
321five × 22five
in base 5
Respuesta :
LammettHash
LammettHash
06-04-2017
[tex]321_5=(3)5^2+(2)5^1+(1)5^0[/tex]
[tex]321_5=\left(\dfrac34\right)10^2+(1)10^1+(1)10^0[/tex]
[tex]321_5=75+10+1[/tex]
[tex]321_5=86_{10}[/tex]
[tex]22_5=(2)5^1+(2)5^0=(1)10^1+(2)10^0=12_{10}[/tex]
[tex]321_5\times22_5=86_{10}\times12_{10}=1032_{10}[/tex]
[tex]\dfrac{1032}5=206+\dfrac25[/tex]
[tex]\dfrac{206}5=41+\dfrac15[/tex]
[tex]\dfrac{41}5=8+\dfrac15[/tex]
[tex]\dfrac85=1+\dfrac35[/tex]
[tex]\dfrac15=0+\dfrac15[/tex]
[tex]\implies1032_{10}=13112_5[/tex]
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