Millamarie
Millamarie Millamarie
  • 07-03-2017
  • Mathematics
contestada

In triangle JKL, solve for x

In triangle JKL solve for x class=

Respuesta :

Аноним Аноним
  • 07-03-2017
I hope this helps you



sin27=0.45=34/x



x=34/0.45


x=75.55



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sguilarte8 sguilarte8
  • 10-07-2020

Answer:  x = 74.89

Step-by-step explanation:

sin 27= opp/hyp = 34/x

x(sin 27)/(sin 27) = 34/(sin 7)

x(0.453990499)/(0.453990499) = 34/0.453990499

x= 74.89

Im actually working on this question rn, and i was a little confused so i came here but turns out i just put some other  ratio on my calc. Hope this helped.

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