06-03-2017
Mathematics

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The perimeter of a skinny rectangle is 264 inches. It's length is 11 times it's with find the width length and area of the rectangle

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rarrininger rarrininger

06-03-2017

P=2(L+W)
264= 2(11W+W)
264/2=2/2(12W)
132 = 12W
132/12= 12W/12
W= 11
L= 11 * 11
L =121

Area of a rectangle = W * L
Area of a rectangle = 11 * 121
Area of a rectangle = 1,331 in²

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