minahilr18 minahilr18
  • 09-09-2022
  • Mathematics
contestada

f(x)=4x^2-x-3, find x when f(x)= -3

Respuesta :

janmilczek
janmilczek janmilczek
  • 09-09-2022

Answer:

x = 0 or x = 1/4

Step-by-step explanation:

f(x) = 4x^2-x-3 = -3

4x^2 - x - 3 = -3

4x^2 - x = 0

x(4x - 1) = 0

x = 0 or 4x - 1 = 0

x = 0 or x = 1/4

Answer Link
wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 09-09-2022

Answer:

The values for x are x =0  x = 1/4

Step-by-step explanation:

f(x)=4x^2-x-3

find f(x) = -3

Let f(x) = -3

Solve for x

-3 = 4x^2-x-3

Add 3 to each side

-3+3 = 4x^2-x-3+3

0  = 4x^2-x

Factor out an x

0 = x( 4x-1)

Using the zero product property

0 = x    4x-1 =0

0=x     4x=1

0=x   x = 1/4

The values for x are x =0  x = 1/4

Answer Link

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