Answer:
Consider points (1, 0) and (2, 2)
[tex]{ \tt{y = mx + c}} \\ [/tex]
m is the slope
[tex]{ \tt{m = \frac{2 - 0}{2 - 1} = 2 }} \\ [/tex]
Therefore
[tex]{ \tt{y = 2x + c}}[/tex]
consider point (1, 0);
[tex]{ \tt{0 = (2 \times 1) + c}} \\ { \tt{c = - 2}}[/tex]
Equation of line is;
[tex]{ \tt{y = 2x - 2}}[/tex]
