Hi.
Answer:
[tex]\left(4x-1\right)^2\left(3x^2+3x-5\right)^2[/tex]
Step-by-step explanation:
[tex](aa=a^2) \left(4x-1\right)\left(4x-1\right)=\left(4x-1\right)^2\\=\left(4x-1\right)^2\left(3x^2+3x-5\right)\left(3x^2+3x-5\right)\\\left(3x^2+3x-5\right)\left(3x^2+3x-5\right)=\left(3x^2+3x-5\right)^2\\=\left(4x-1\right)^2\left(3x^2+3x-5\right)^2[/tex]
