find minimum and max y value because that is what range is we see it opens up becasue 3 is positive x value of vertex is -b/2a when you have f(x)=ax^2+bx+c
f(x)=3x^2+6x-8 vertex is -6/(2*3)=-6/6=-1 find y value by subsituiong it for x f(-1)=3(-1)^2+6(-1)-8 f(-1)=3(1)-6-8 f(-1)=3-14 f(-1)=-11
