crazycountrygirl19
crazycountrygirl19 crazycountrygirl19
  • 08-02-2017
  • Mathematics
contestada

Given that f(x) = x2 + 2x + 3 and g(x) = quantity of x plus four, over three, solve for f(g(x)) when x = 2. 2 5 11 33

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apologiabiology
apologiabiology apologiabiology
  • 08-02-2017
basically sub g(x) for x in f(x)

[tex]f(g(x))=( g(x))^2+2(g(x))+3[/tex]
[tex]f(g(x))=( \frac{x+4}{3})^2+2( \frac{x+4}{3})+3[/tex]
we don't need to simplify

[tex]f(g(2))=( \frac{2+4}{3})^2+2( \frac{2+4}{3})+3[/tex]
[tex]f(g(2)))=( \frac{6}{3})^2+2( \frac{6}{3})+3[/tex
[tex]f(g(2)))=(2)^2+2(2)+3[/tex
f(g(2))=4+4+3
f(g(2))=11
answer is 11
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