Respuesta :

Let's see

In ∆ABE and ∆CBE

  • BE=BE(Common side)
  • AE=EC[Diagonals of a parallelogram bisect each other]
  • <AEB=<BEC[90°]

So by

SAS congruence the triangles are congruent

AB=BC

  • Proved

Fact:-

It's already given AC is perpendicular to BD

  • It means diagonals are perpendicular to each other

According to general property of rhombus this parallelogram is also a rhombus.

So sides are equal hence AB =BC

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