jimenezeman06 jimenezeman06
  • 08-07-2022
  • Mathematics
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30 MORE POINTS FOR THIS

30 MORE POINTS FOR THIS class=

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subtomex0
subtomex0 subtomex0
  • 08-07-2022

[tex]y = \frac{1}{x - 3} + 7[/tex]

[tex]x = \frac{1}{y - 3} + 7[/tex]

[tex]x - 7 = \frac{1}{y - 3} [/tex]

[tex]y - 3 = \frac{1}{x - 7} [/tex]

[tex]y = \frac{1}{x - 7} + 3[/tex]

where x≠7

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