user2134452 user2134452
  • 10-06-2022
  • Mathematics
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Medunno13
Medunno13 Medunno13
  • 11-06-2022

By the Pythagorean theorem, [tex]IH=\sqrt{8^{2}-3^{2}}=\sqrt{55}[/tex].

So,

[tex]\sin J=\frac{\sqrt{55}}{8}\\\\\cos J=\frac{3}{8}\\\\\tan J=\frac{\sqrt{55}}{3}[/tex]

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