The value of x in the triangle is 109.5
How to solve for x?
The value of x can be calculated using the following law of cosine
a^2 = b^2 + c^2 - 2bc cos(A)
Where:
a = x
b = 63
c = 61
A = 124
So, we have:
x^2 = 63^2 + 61^2 - 2 * 63 * 61 cos(124)
Evaluate
x^2 = 11987.96
Take the square root of both sides
x = 109.5
Hence, the value of x is 109.5
Read more about law of cosine at:
https://brainly.com/question/4372174
#SPJ1
