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[tex] \binom{{(x ^{2} + \frac{7}{3} x - \frac{17}{3}}) = 3}{x ^{2} + \frac{7}{3} x + \frac{49}{36} - \frac{49}{36} - \frac{17}{3} }[/tex]

How to solve it Heeeeeeeellp​
Will give BRAINIEST if the answer and explaination are correct

Respuesta :

Simplify first

[tex]\\ \rm\Rrightarrow x^2+\dfrac{7}{3}x-\dfrac{17}{3}=3[/tex]

[tex]\\ \rm\Rrightarrow 3x^2+7x-17=9[/tex]

[tex]\\ \rm\Rrightarrow 3x^2+7x-26=0\dots(1)[/tex]

And

[tex]\\ \rm\Rrightarrow x^2+\dfrac{7}{3}x+\dfrac{49}{36}-\dfrac{49}{36}-\dfrac{7}{3}=0[/tex]

[tex]\\ \rm\Rrightarrow 3x^2+7x-7=0\dots (2)[/tex]

Both the equations have equal rate of change or slope

Hence they have no intersection point

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