Answer:
2.174 gm
Explanation:
PV = nRT n = number of moles
R = gas constant = .082057 L-atm/(K-mol)
T must be in units of K
.870 (3.95) = n (.082057)(35+273.15)
solve for n = .1359 moles
Methane mole weight (CH4) = 16 gm / mole
.1359 moles * 16 gm/mole = 2.174 gm
