Answer:
In alphabetic order:
x can be found with pythagorean theorem, since triangle ADC is right in D.
[tex]x= \sqrt {7^2-2.2^2} \approx 6.6[/tex]
y and z are 7 times respectively the sine and cosine of angle ACB.
[tex]y= 7sin\ 52\° \approx 5.5\\z=7 cos\ 52\° \approx 4.3[/tex]
Finally, [tex]\theta[/tex] can be calculated by determining the arc sine (or inverse sine) of the ratio CD over AC
[tex]\theta = sin^{-1} (\frac{2.2}7) \approx 18.3\°[/tex]
