For a cell operated to produce a constant voltage of 1.50 V, the electrical work done is mathematically given as
W=2.077*10^{-7}
What is the electrical work done?
Generally, the volume of Br2 is mathematically given as
[tex]Vb=\frac{0.38*3.12}{159.809}[/tex]
Vb=7.18*10^-3ml
Therefore, the quantity of charge
q=(1.436*10^-2)*9.644*10^4
q=1.385^{-4}c
In conclusion, work done
W=Eq
W=1.50*1.385^{-4}
W=2.077*10^{-7}
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