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→ Here,

  • y varies directly as x means that y = kx
  • here value of (k) is not known

by substituting the values of x and y, y = 18 when x = 12

[tex]\rm{y = kx} \\ \\ \rm{18 = 12k} \\ \\ \rm{k = \cancel \frac{18}{12} } \\ \\ \rm{ k = 1.5}[/tex]

Now, substituting value of k nd x in y = kx

  • x = 132
  • k = 1.5
  • in y = kx

[tex] \rm{y = (1.5 \times 60 )} \\ \\ \rm{y = 90}[/tex]

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