[tex]y = - \frac{28}{48x - 15} - \frac{125}{321} [/tex]is the answer.
Step-by-step explanation:
For this question,
• First, find the slope of the line parallel to the line 5/8x−7/6y=2 :-
[tex]m = - \frac{28}{ - 15 + 48x} [/tex]
•Second, find the equation of the line,
[tex]y = - \frac{28}{48x - 15} - \frac{125}{321} [/tex]
