Answer:
-4
-4
1
-8
1
Step-by-step explanation:
[tex]x^2-4x-8=0[/tex]
Comparing [tex]ax^2+bx+c=0[/tex]
⇒ a = 1, b = -4 and c = -8
Substituting these values into the quadratic formula:
[tex]x=\frac{-(-4)\pm\sqrt{(-4)^2-4(1)(-8)} }{2(1)}[/tex]
(The numbers you need to fill in the blanks are in bracket)
