Answer:
[tex]\frac{14}{t^5m^2}[/tex] The answer is D.
Step-by-step explanation:
[tex]\frac{7s^0t^-5}{ 2^-1m^2}[/tex]
= [tex]\frac{7(1)(2^1)}{t^5m^2}[/tex]
= [tex]\frac{14}{t^5m^2}[/tex]
since u don't want to help its 2000
