Answer: 4y/(y+3)
Explanation:
{(2y)(4y-12)}/{(y-3)(2y+6)}
= (8y^2 - 24y)/(2y^2 + 6y - 6y - 18)
= (8y^2 - 24y)/(2y^2 - 18)
= {8y(y-3)}/{2(y+3)(y-3)}
= 2 * 4y/{2(y+3)}
= 4y/(y+3)
