Answer:
071r3
Step-by-step explanation:
So you solve this one part at a time.
3 can go into 21 when multiplied by 7.
so put a o over the 2, and a 7 over the one.
and a 21 under 21.
Now 3 can go into 4 when multiplied by 1.
so put a 1 over the 4,
and a 3 under it.
4-3=1
Now 3 can't go into one, so you will add a dicimal, (represented as r already) and then the 1 becomes 10. now 3 can go into ten when multiplied by 3.
so put a 3 next to the r, and a 9 under the ten.
10-9=1
Now it's repeated.
